Conjugate Acids & Bases (Cambridge (CIE) A Level Chemistry): Revision Note
Conjugate Acids & Bases
A Brønsted acid is a species that can donate a proton
For example, hydrogen chloride (HCl) is a Brønsted acid as it can lose a proton to form a hydrogen (H+) and chloride (Cl-) ion
HCl (aq) → H+ (aq) + Cl- (aq)
A Brønsted base is a species that can accept a proton
For example, a hydroxide (OH-) ion is a Brønsted base as it can accept a proton to form water
OH- (aq) + H+ (aq) → H2O (l)
In an equilibrium reaction, the products are formed at the same rate as the reactants are used
This means that at equilibrium, both reactants and products are present in the solution
For example, ethanoic acid (CH3COOH) is a weak acid that partially dissociates in solution
When equilibrium is established there are CH3COOH, H2O, CH3COO- and H3O+ ions present in the solution
The species that can donate a proton are acids and the species that can accept a proton are bases
The reactant CH3COOH is linked to the product CH3COO- by the transfer of a proton from the acid (CH3COOH) to the base (CH3COO-)
Similarly, the H2O molecule is linked to H3O+ ion by the transfer of a proton
These pairs are therefore called conjugate acid-base pairs
A conjugate acid-base pair is two species that are different from each other by an H+ ion
Conjugate here means related
In other words, the acid and base are related to each other by one proton difference
Conjugate acid-base pairs are a pair of reactants and products that are linked to each other by the transfer of a proton
For example, in the equilibrium reaction below, the ethanoic acid (CH3COOH) partially dissociates in solution to form ethanoate (CH3COO-) and hydrogen (H+) ions
When equilibrium is established there are CH3COOH, H2O, CH3COO- and H3O+ ions present in the solution
The species that can donate a proton are acids and the species that can accept a proton are bases
In the forward reaction:
The acid CH3COOH is linked to the base CH3COO-
CH3COO- is, therefore, the conjugate base of CH3COOH
CH3COOH - CH3COO- = conjugate acid-base pair
The base H2O is linked to the acid H3O+
H3O+ is, therefore, the conjugate acid of H2O
In the reverse reaction
The base CH3COO- is linked to the acid CH3COOH
CH3COOH is therefore conjugate acid of CH3COO-
CH3COO- - CH3COOH = conjugate acid-base pair
The acid H3O+ is linked to the base H2O
H2O is, therefore, the conjugate base of H3O+
H3O+ - H2O = conjugate acid-base pair
Worked Example
Identifying conjugate acid-base pairs
Identify the conjugate acid-base pairs in the following equilibrium reaction:
NH3 (g) + H2O (l) NH4+ (aq) + OH– (aq)
Answer:
In the forward reaction:
NH4+ is the conjugate acid of the base NH3
OH- is the conjugate base of the acid H2O
In the reverse reaction
NH3 is the conjugate base of the acid NH4+
H2O is the conjugate acid of the base OH–
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