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Conjugate Acids & Bases (CIE A Level Chemistry)

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Conjugate Acids & Bases

  • A Brønsted acid is a species that can donate a proton
    • For example, hydrogen chloride (HCl) is a Brønsted acid as it can lose a proton to form a hydrogen (H+) and chloride (Cl-) ion

HCl (aq) → H+ (aq) + Cl- (aq)

  • A Brønsted base is a species that can accept a proton
    • For example, a hydroxide (OH-) ion is a Brønsted base as it can accept a proton to form water

OH- (aq) + H+ (aq) → H2O (l)

  • In an equilibrium reaction, the products are formed at the same rate as the reactants are used
  • This means that at equilibrium, both reactants and products are present in the solution
  • For example, ethanoic acid (CH3COOH) is a weak acid that partially dissociates in solution
  • When equilibrium is established there are CH3COOH, H2O, CH3COO- and H3O+ ions present in the solution
  • The species that can donate a proton are acids and the species that can accept a proton are bases

Conjugate Acids & Bases equation 1

  • The reactant CH3COOH is linked to the product CH3COO- by the transfer of a proton from the acid (CH3COOH) to the base (CH3COO-)
  • Similarly, the H2O molecule is linked to H3O+ ion by the transfer of a proton
  • These pairs are therefore called conjugate acid-base pairs
  • A conjugate acid-base pair is two species that are different from each other by an H+ ion
    • Conjugate here means related
    • In other words, the acid and base are related to each other by one proton difference
  • Conjugate acid-base pairs are a pair of reactants and products that are linked to each other by the transfer of a proton
  • For example, in the equilibrium reaction below, the ethanoic acid (CH3COOH) partially dissociates in solution to form ethanoate (CH3COO-) and hydrogen (H+) ions
  • When equilibrium is established there are CH3COOH, H2O, CH3COO- and H3O+ ions present in the solution
  • The species that can donate a proton are acids and the species that can accept a proton are bases

Conjugate Acids & Bases equation 1

  • In the forward reaction:
    • The acid CH3COOH is linked to the base CH3COO-
    • CH3COO- is, therefore, the conjugate base of CH3COOH

CH3COOH - CH3COO- = conjugate acid-base pair

    • The base H2O is linked to the acid H3O+
    • H3O+ is, therefore, the conjugate acid of H2O
  • In the reverse reaction
    • The base CH3COO- is linked to the acid CH3COOH
    • CH3COOH is therefore conjugate acid of CH3COO-

CH3COO- - CH3COOH = conjugate acid-base pair

    • The acid H3O+ is linked to the base H2O
    • H2O is, therefore, the conjugate base of H3O+

H3O+ - H2O = conjugate acid-base pair

Worked example

Identifying conjugate acid-base pairs

Identify the conjugate acid-base pairs in the following equilibrium reaction:

NH3 (g) + H2O (l) begin mathsize 16px style rightwards harpoon over leftwards harpoon end style NH4+ (aq) + OH (aq)

Answer:

  • In the forward reaction:
    • NH4+ is the conjugate acid of the base NH3
    • OH- is the conjugate base of the acid H2O
  • In the reverse reaction
    • NH3 is the conjugate base of the acid NH4+
    • H2O is the conjugate acid of the base OH

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Philippa

Author: Philippa

Expertise: Chemistry

Philippa has worked as a GCSE and A level chemistry teacher and tutor for over thirteen years. She studied chemistry and sport science at Loughborough University graduating in 2007 having also completed her PGCE in science. Throughout her time as a teacher she was incharge of a boarding house for five years and coached many teams in a variety of sports. When not producing resources with the chemistry team, Philippa enjoys being active outside with her young family and is a very keen gardener.