Standard Cell Potential Calculations
- Once the Eꝋ of a half-cell is known, the potential difference or voltage or emf of an electrochemical cell made up of any two half-cells can be calculated
- These could be any half-cells and neither have to be a standard hydrogen electrode
- The standard cell potential (Ecellꝋ) can be calculated by subtracting the less positive Eꝋ from the more positive Eꝋ value
- The half-cell with the more positive Eꝋ value will be the positive pole
- By convention this is shown on the right-hand side in a conventional cell diagram, so is termed Erightꝋ
- The half-cell with the less positive Eꝋ value will be the negative pole
- By convention this is shown on the left-hand side in a conventional cell diagram, so is termed Eleftꝋ
Ecellꝋ = Erightꝋ - Eleftꝋ
- Since oxidation is always on the left and reduction on the right, you can also use this version
Ecellꝋ = Ereductionꝋ - Eoxidationꝋ
Worked example
Calculating the standard cell potential
Calculate the standard cell potential for the electrochemical cell below and explain why the Cu2+ / Cu half-cell is the positive pole. The half-equations are as follows:
Cu2+ (aq) + 2e- ⇌ Cu (s) Eꝋ = +0.34 V
Zn2+ (aq) + 2e- ⇌ Zn (s) Eꝋ = −0.76 V
Answer
- Step 1: Calculate the standard cell potential. The copper is more positive so must be the right hand side.
- Ecellꝋ = Erightꝋ - Eleftꝋ
- Ecellꝋ = (+0.34) - (-0.76) = +1.10 V
- The voltmeter will therefore give a value of +1.10 V
- Step 2: Determine the positive and negative poles
-
- The Cu2+ / Cu half-cell is the positive pole as its Eꝋ is more positive than the Eꝋ value of the Zn2+ / Zn half-cell
Examiner Tip
- Students often confuse the redox process that take place in voltaic cells and electrolytic cells.
- An easy way to remember is the phrase RED CATS: REDuction takes place at the CAThode.
OR
AN OX. OXidation takes place at the ANode