Enthalpy Change of Hydration & Solution
Enthalpy change of solution
- The standard enthalpy change of solution (ΔHsolθ) is the enthalpy change when 1 mole of an ionic substance dissolves in sufficient water to form a very dilute solution
- The symbol (aq) is used to show that the solid is dissolved in sufficient water
- For example, the enthalpy changes of solution for potassium chloride are described by the following equations:
KCl (s) + aq → KCl (aq)
OR
KCl (s) + aq → K+ (aq) + Cl– (aq)
- ΔHsolθ can be exothermic (negative) or endothermic (positive)
Enthalpy change of hydration
- The lattice energy (ΔHlattθ) of KCl is -711 kJ mol-1
- This means that 711 kJ mol-1 is released when the KCl ionic lattice is formed
- Therefore, to break the attractive forces between the K+ and Cl- ions, +711 kJ mol-1 is needed
- However, the ΔHsolθ of KCl is +26 kJ mol-1
- This means that another +685 kJ mol-1 (711 - 26) is required to break the KCl lattice
- This is compensated for by the standard enthalpy change of hydration (ΔHhydθ)
- For example, the enthalpy change of hydration for magnesium ions is described by the following equation:
- The standard enthalpy change of hydration (ΔHhydθ) is the enthalpy change when 1 mole of a specified gaseous ion dissolves in sufficient water to form a very dilute solution
Mg2+(g) + aq → Mg2+(aq)
-
- Hydration enthalpies are the measure of the energy that is released when there is an attraction formed between the ions and water molecules
- Hydration enthalpies are exothermic
- When an ionic solid dissolves in water, positive and negative ions are formed
- Water is a polar molecule with a δ- oxygen (O) atom and δ+ hydrogen (H) atoms which will form ion-dipole attractions with the ions present in the solution
- The oxygen atom in water will be attracted to the positive ions and the hydrogen atoms will be attracted to the negative ions
- Since the ΔHhydθ of KCl is -685 kJ mol-1, 685 kJ mol-1 is released in forming these ion-dipole attractions when KCl dissolves in water
- This compensates for the remaining +685 kJ mol-1 which was needed to break down the KCl lattice
Interactions of polar water molecules and other ions in solution
The polar water molecules will form ion-dipole bonds with the ions in solution (a) causing the ions to become hydrated (b)