Mass Spectrometry (Cambridge (CIE) A Level Chemistry)
Revision Note
Interpreting Mass Spectra
Mass spectroscopy is an analytical technique used to identify unknown compounds
The molecules in the small sample are bombarded with high energy electrons which can cause the molecule to lose an electron
This results in the formation of a positively charged molecular ion with one unpaired electron
One of the electrons in the pair has been removed by the beam of electrons
MOLECULE MOLECULE+• + e–
MOLECULE+• represents the molecular ion
The molecular ion can further fragment to form new ions, molecules, and radicals
Fragmentation of a molecule in mass spectroscopy
The same molecule can produce several different fragments in mass spectroscopy
These fragmentation ions are accelerated by an electric field
Based on their mass (m) to charge (e) ratio, the fragments of ions are then separated by deflecting them into the detector
For example, an ion with mass 16 and charge 2+ will have a m/e value of 8
The smaller and more positively charged fragment ions will be detected first as they will get deflected the most and are more attracted to the negative pole of the magnet
Each fragment corresponds to a specific peak with a particular m/e value in the mass spectrum
The base peak is the peak corresponding to the most abundant ion
Isotopes
Isotopes are different atoms of the same element that contain the same number of protons and electrons but a different number of neutrons.
These are atoms of the same elements but with different mass number
For example, Cl-35 and Cl-37 are isotopes as they are both atoms of the same element (chlorine, Cl) but have a different mass number (35 and 37 respectively)
Mass spectroscopy can be used to find the relative abundance of the isotopes experimentally
The relative abundance of an isotope is the proportion of one particular isotope in a mixture of isotopes found in nature
For example, the relative abundance of Cl-35 and Cl-37 is 75% and 25% respectively
This means that in nature, 75% of the chlorine atoms is the Cl-35 isotope and 25% is the Cl-37 isotope
The heights of the peaks in mass spectroscopy show the proportion of each isotope present
Example mass spectrum of boron
The peak heights show the relative abundance of the boron isotopes: boron-10 has a relative abundance of 19.9% and boron-11 has a relative abundance of 80.1%
Worked Example
In a sample of iron, the ions 54Fe2+ and 56Fe3+ are detected.
Calculate the m/e value ratio and determine which ion is deflected more inside the spectrometer.
Answer:
m/e (54Fe2+) =
m/e (56Fe3+) =
Examiner Tips and Tricks
A small m/e value corresponds to fragments that are either small or have a high positive charge or a combination of both
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