Free Radical Substitution (Cambridge (CIE) A Level Chemistry) : Revision Note
Free Radical Substitution Mechanism
Alkanes can undergo free-radical substitution in which a hydrogen atom gets substituted by a halogen (chlorine/bromine)
Ultraviolet light (sunlight) is needed for this substitution reaction to occur
Reacting an alkane with bromine

The fact that the bromine colour has disappeared only when mixed with an alkane and placed in sunlight suggests that the ultraviolet light is essential for the free radical substitution reaction to take place
The free radical substitution of methane involves the standard steps:
Initiation
Propagation
Termination
Initiation step
The covalent Cl-Cl bond is broken by energy from the UV light
Each atom takes one electron from the covalent bond
This produces two radicals in a homolytic fission reaction
Cl–Cl 2Cl•
Propagation step
The halogen free radicals are very reactive and will attack the unreactive alkanes
One of the methane C-H bond breaks homolytically to produce an alkyl radical
CH4 + Cl• → •CH3 + HCl
The alkyl radical can attack another chlorine molecule to form a halogenoalkane
This also regenerates the chlorine free radical
•CH3 + Cl2 → CH3Cl + Cl•
The regenerated chlorine free radical can then repeat the cycle
This reaction is not very suitable for preparing specific halogenoalkanes as a mixture of substitution products are formed
If there is enough chlorine/bromine present, all the hydrogens in the alkane will eventually get substituted (eg. ethane will become C2Cl6/C2Br6)
Termination step
Multiple products are possible, dependent on the radicals involved
For example, in the single substitution of methane with chlorine:
•CH3 + Cl• → CH3Cl
•CH3 + •CH3 → CH3CH3
Cl• + Cl• → Cl2
Examiner Tips and Tricks
If you are asked to give an equation for the termination step of a free radical reaction / mechanism, you should not give the equation reforming the original halogen as this is often marked as "ignore" on mark schemes.
Free radical substitution using bromine instead of chlorine is possible and follows similar initiation, propagation and termination steps
Further substitution
Often, free radical reactions are not very suitable for preparing specific halogenoalkanes as a mixture of substitution products are formed
If there is enough chlorine / bromine present, all the hydrogens in the alkane will eventually get substituted
For example, methane could be substituted to become chloromethane and then further substituted
Single substitution:
CH4 + Cl• → •CH3 + HCl
•CH3 + Cl2 → CH3Cl + Cl•
Second substitution:
CH3Cl + Cl• → •CH2Cl + HCl
•CH2Cl + Cl2 → CH2Cl2 + Cl•
Third substitution:
CH2Cl2 + Cl• → •CHCl2 + HCl
•CHCl2 + Cl2 → CHCl3 + Cl•
Complete substitution:
CHCl3 + Cl• → •CCl3 + HCl
•CCl3 + Cl2 → CCl4 + Cl•
Examiner Tips and Tricks
You could be asked to draw the mechanism for initiation and termination steps for free radical substitution
This mechanism will use half-headed arrows to show the movement of one electron (double-headed arrows show the movement of a pair of electrons)
A half-headed arrow is known as a ‘fish hook’ arrow.
Initiation:

Termination:

The key is the use of the ‘fish hook’ arrow to show the homolytic fission of the bond in initiation and the formation of the bond in termination.
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