Determining Electronic Configuration (Cambridge (CIE) A Level Chemistry): Revision Note

Exam code: 9701

Richard Boole

Last updated

Determining Electronic Configurations

  • Electron configuration shows how electrons are arranged in shells, subshells, and orbitals.

  • There are two formats:

    • Full configuration; lists all electrons from 1s onward

    • Shorthand configuration; uses the symbol of the nearest noble gas in brackets to represent inner electrons (e.g. [Ar])

  • Ions form when atoms gain or lose electrons:

    • Anions (negative) form by adding electrons to the outer shell

    • Cations (positive) form by removing electrons from the outer shell

  • Transition metals:

    • Fill the 4s before 3d when neutral

    • Lose electrons from 4s first, not 3d, when forming ions

  • In the Periodic Table the elements are grouped into blocks based on their valence subshell:

    • s-block: valence electrons in an s orbital

    • p-block: valence electrons in a p orbital

    • d-block: valence electrons in a d orbital

    • f-block: valence electrons in an f orbital

The blocks of the Periodic Table

Diagram of periodic table blocks: s-block (2s-7s, blue), d-block (3d-5d, orange), p-block (2p-6p, green), f-block (4f-5f, red).
The elements can be divided into the s, p, d or f block, according to their outer shell electron configuration

Examples

  • Electronic configuration of Fe

    • Atomic number = 26 so there are 26 electrons

    • Full configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d6

    • Shorthand: [Ar] 4s2 3d6

  • Electronic configuration of Fe2+

    • Atomic number = 26 so there are 26 electrons, but the Fe2+ ion only has 24 electrons

    • Electrons are removed from the 4s orbital before the 3d

    • Full configuration: 1s2 2s2 2p6 3s2 3p6 3d6

    • Shorthand: [Ar] 3d6

Exceptions to the Aufbau principle

  • Chromium and copper have the following electron configurations:

    • Cr is [Ar] 3d5 4s1 not [Ar] 3d4 4s2

    • Cu is [Ar] 3d10 4s1 not [Ar] 3d9 4s2

  • This is because the [Ar] 3d5 4s1 and [Ar] 3d10 4s1 configurations are energetically favourable

  • By promoting an electron from 4s to 3d, these atoms achieve a half full or full d-subshell, respectively

Worked Example

  • Write down the full and shorthand electron configuration of the following elements:

    1. Potassium

    2. Calcium

    3. Gallium

    4. Ca2+

    Answer:

    • Potassium

      • Electrons: 19

      • Full configuration: 1s2 2s2 2p6 3s2 3p6 4s¹

      • Shorthand: [Ar] 4s¹

      • Note: Argon (Ar) has 18 electrons and is the previous noble gas

    • Calcium

      • Electrons: 20

      • Full configuration: 1s2 2s2 2p63s2 3p6 4s2

      • Shorthand: [Ar] 4s²

      • Note: 4s is filled before 3d because it is lower in energy

    • Gallium

      • Electrons: 31

      • Full configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p1

      • Shorthand: [Ar] 3d10 4s2 4p1

      • Note: Includes filled 3d subshell after argon

    • Calcium 2+ ion

      • Electrons: 18 (after losing two 4s electrons)

      • Full configuration: 1s2 2s2 2p6 3s2 3p6

      • Shorthand: [Ar]

      • Note: Ca²⁺ has the same configuration as argon

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Richard Boole

Author: Richard Boole

Expertise: Chemistry Content Creator

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.