pKₐ (AQA A Level Chemistry): Revision Note
pKₐ
The range of values of Ka is very large and for weak acids, the values themselves are very small numbers
Table of Ka values
![Table of Ka values, downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/10/5.6.2-Table-of-Ka-values.png)
For this reason it is easier to work with another term called pKa
The pKa is the negative log of the Ka value, so the concept is analogous to converting [H+] into pH values
pKa = -logKa
Looking at the pKa values for the same acids:
Table of pKa values
![Table of pKa values, downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/10/5.6.2-Table-of-pKa-values.png)
The range of pKa values for most weak acids lies between 3 and 7
Worked Example
Finding Ka and pKa
At 298 K, a solution of 0.100 mol dm-3 ethanoic acid has a hydrogen ion concentration of 1.32 x 10-3 mol dm-3. Calculate the Ka & pKa of the acid.
Answer
Step 1: Write down the equation for the partial dissociation of ethanoic acid
CH3COOH (aq) ⇌ H+ (aq) + CH3COO- (aq)
Step 2: Write down the equilibrium expression to find Ka
![Calculating pH, Ka, pKA & Kw equation 2](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/3.-Calculating-pH-Ka-pKA-Kw-equation-2.png)
Step 3: Simplify the expression
The ratio of H+ to CH3COO- is 1:1
The concentration of H+ and CH3COO- is, therefore, the same
The equilibrium expression can be simplified to:
![Calculating pH, Ka, pKA & Kw equation 3](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/3.-Calculating-pH-Ka-pKA-Kw-equation-3.png)
Step 4: Substitute the values into the expression to find Ka
![Calculating pH, Ka, pKA & Kw equation 4](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/3.-Calculating-pH-Ka-pKA-Kw-equation-4.png)
![Calculating pH, Ka, pKA & Kw equation 5](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/3.-Calculating-pH-Ka-pKA-Kw-equation-5.png)
= 1.74 x 10-5
Step 5: Determine the units of Ka
![Calculating pH, Ka, pKA & Kw equation 6](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/3.-Calculating-pH-Ka-pKA-Kw-equation-6.png)
![Calculating pH, Ka, pKA & Kw equation 7](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/01/3.-Calculating-pH-Ka-pKA-Kw-equation-7.png)
= mol dm-3
The value of Ka is therefore 1.74 x 10-5 mol dm-3
Step 6: Find pKa
pKa = - log10Ka
= - log10 (1.74 x 10-5)
= 4.76
Kₐ from pH
How are Ka values found?
If we neutralise a weak acid with a strong base such sodium hydroxide the equation for the reaction is:
HA (aq) + NaOH (aq) → NaA (aq) + H2O (l)
HA (aq) + OH- (aq) → A- (aq) + H2O (l)
When half of the acid has been neutralised the concentration of [HA] is equal to the concentration of [A-]
Since the acid is poorly dissociated it is assumed all the A- comes from the product rather than HA dissociating
This simplifies the expression to
![Ka at half neutralisation, downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/10/5.6.2-Ka-at-half-neutralisation.png)
In practice, to find Ka the pH of a weak acid is measured as it is neutralised by a strong base and a graph is plotted for pH versus volume of base added
This type of graph is known as a pH titration curve
A vertical tie-line is drawn to the curve at half the volume of base needed for neutralisation
At this point pKa = pH, so by reading off the pH value from the y-axis, you find the Ka of the acid
![5.6.2 pKa from pH, downloadable AS & A Level Chemistry revision notes](https://cdn.savemyexams.com/cdn-cgi/image/f=auto,width=3840/https://cdn.savemyexams.com/uploads/2021/11/5.6.2-pKa-from-pH.png)
Finding the Ka of a weak acid from a pH titration curve
Examiner Tips and Tricks
You can regard the symbol p as meaning -log10 of a value. You don't need to include the 10 as 'log' means log base 10. If a natural logarithm (base e) is required it is given the symbol ln. Other uses of p include pOH and pKw . The latter gives a useful shortcut in problem-solving:
Kw = [H+][OH-] = 1.00 x 10-14 mol2 dm-6 at 298 K
-logKw = -log[H+] + (-log[OH-]) = -log(1.00 x 10-14)
pKw = pH + pOH = 14.00
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