Kp Expressions (AQA A Level Chemistry)
Revision Note
Kp Expressions
We have seen previously that equilibrium reactions can be quantified by reference to an equilibrium expression and equilibrium constant
The equilibrium expression links the equilibrium constant, Kc, to the concentrations of reactants and products at equilibrium taking the stoichiometry of the equation into account
So, for a given reaction:
aA + bB ⇌ cC + dD
Kc is defined as follows:
Equilibrium expression linking the equilibrium concentration of reactants and products at equilibrium
Solids are ignored in equilibrium expressions
The Kc of a reaction is constant and only changes if the temperature of the reaction changes
Gaseous Equilibria
This section covers how we manage gases in calculating the equilibrium constant and how an equilibrium yield is affected by the partial pressures of reactants and products
Many industrial process involve reactions between gases so this application has important consequences for controlling reaction conditions
In the generic example above, if all the substances are gases, we can show the equation with that state symbol
aA (g) + bB (g) ⇌ cC (g) + dD (g)
We can write a different equilibrium expression in terms of the partial pressure of the gases
This equilibrium constant is called Kp and is defined as follows
Equilibrium expression linking the partial pressures of reactants and products at equilibrium
Solids and liquids are ignored in Kp equilibrium expressions
The Kp of a reaction is constant and only changes if the temperature of the reaction changes
Worked Example
Write a Kp expression for the following equilibria and deduce the units of Kp :
N2 (g) + 3H2 (g) ⇌ 2NH3 (g)
2SO2 (g) + O2 (g) ⇌ 2SO3 (g)
Answer 1
Answer 2
Examiner Tips and Tricks
You are only required to know how to write Kp expressions for homogeneous systems, that is, where all the substances present are gases.
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