Identifying Anions & Cations
REQUIRED PRACTICAL 4
Test Tube Reactions
- Simple test tube reactions can be done to identify the following ions:
- Group 2 ions (M2+)
- Ammonium ions (NH4+)
- Halide ions (X-)
- Hydroxide ions (OH-)
- Carbonate ions (CO32-)
- Sulfate ions (SO42-)
- If the sample to be tested is a solid, then it must be dissolved in deionised water and made into an aqueous solution
Testing for Group 2 Metals
- Four test tubes should be placed in a test tube rack
- Around 10 drops of 0.1 mol dm-3 barium chloride solution should be added to the first test tube
- Around 10 drops of dilute sodium hydroxide solution (NaOH) should be added to the same test tube
- Swirl the test tube carefully to mix well
- Continue to add sodium hydroxide dropwise to the test tube, until it is in excess
- This should then be repeated in the other test tubes, for calcium bromide solution, magnesium chloride solution and strontium chloride solution
- Any observations should be noted down in a suitable results table
- The same test as above can also be done using ammonia solution and sulfuric acid solution
The positive results testing for the presence of Group 2 ions
Testing for Ammonium Ions
- About 10 drops of a solution containing ammonium ions, such as ammonium chloride, should be added to a clean test tube
- About 10 drops of sodium hydroxide should be added using a pipette
- The test tube should be swirled carefully to ensure that it is mixed well
- The test tube of the solution should then be placed in a beaker of water, and the beaker of water should be placed above a Bunsen burner, so that it can become a water bath
- As the solution is heated gently, fumes will be produced
- A pair of tongs should be used to hold a damp piece of red litmus paper near the mouth of the test tube, to test the fumes
- The red litmus paper will change colour and become blue in the presence of ammonia gas
Damp red litmus paper turning blue in the presence of ammonia gas
Testing for Halide Ions
- The sample being tested should be added using a pipette to a test tube
- The test tube should be placed into a test tube rack
- A small amount of nitric acid should be added to the sample using a pipette, followed by a small amount of silver nitrate solution
- A precipitate will form, either white, cream or yellow, if a halide ion is present in the sample
The white, cream and yellow precipitates formed when halide ions react with silver nitrate solution
- The white precipitate will form if chloride ions are present in the sample
- The white precipitate is AgCl
- The cream precipitate will form if bromide ions are present in the sample
- The cream precipitate is AgBr
- The yellow precipitate will form if iodide ions are present in the sample
- The yellow precipitate is AgI
Further Test using Ammonia
Results of the test with ammonia to further distinguish between silver halide precipitates
Testing for Hydroxide Ions
- A small amount (around 1 cm3) of the solution should be added to a test tube using a pipette
- Test the pH of the solution using red litmus paper or universal indicator paper
- The presence of hydroxide ions will turn the red litmus paper blue and the pH will be clearly alkaline on the universal indicator paper if hydroxide ions are present
Testing for Carbonate Ions
- A small amount (around 1 cm3) of dilute hydrochloric acid should be added to a test tube using a pipette
- An equal amount of sodium carbonate solution should then be added to the test tube using a clean pipette
- As soon as the sodium carbonate solution is added, a bung with a delivery tube should be attached to the test tube
- The delivery tube should transfer the gas which is formed into a different test tube which contains a small amount of limewater (calcium hydroxide solution)
- Carbonate ions will react with hydrogen ions from the acid to produce carbon dioxide gas
- Carbon dioxide gas will turn the limewater milky
When carbon dioxide gas is bubbled into limewater it will turn cloudy as calcium carbonate is produced
Testing for Sulfate Ions
- Acidify the sample with dilute hydrochloric acid and then add a few drops of aqueous barium chloride
- If a sulfate is present then a white precipitate of barium sulfate is formed:
Ba2+ (aq) + SO42- (aq) → BaSO4 (s)
A white precipitate of barium sulfate is a positive result for the presence of sulfate ions
Examiner Tip
HCl is added first to remove any carbonates which may be present and would also produce a precipitate and interfere with the results.