When Mendel crossed two pea plants that were heterozygous for both seed colour and shape, the ratio of phenotypes in the offspring was:
- 9 yellow round
- 3 green round
- 3 yellow wrinkled
- 1 green wrinkled
Some students tried to recreate this investigation using a modern variety of plant that showed the same phenotypic variation in seed colour and shape.a)
The students crossed two of the modern plants that were heterozygous for both seed colour and shape. The results of this cross were:
- 58 yellow and round
- 31 green and round
- 21 yellow and wrinkled
- 2 green and wrinkled
The students used the chi-squared test to compare their data to the expected 9:3:3:1 ratio.
(i) Use the chi-squared formula χ2 = to calculate the χ2 value for these data.
You may use the table below for working out.
χ2 = .............................[3]
Table 17 shows a
χ2 probability table.
Degrees of freedom |
Probability (p) |
0.95 |
0.90 |
0.10 |
0.05 |
0.025 |
0.01 |
1 |
0.00 |
0.02 |
2.71 |
3.84 |
5.02 |
6.64 |
2 |
0.10 |
0.21 |
4.61 |
5.99 |
7.38 |
9.21 |
3 |
0.35 |
0.58 |
6.25 |
7.82 |
9.35 |
11.34 |
4 |
0.71 |
1.06 |
7.78 |
9.49 |
11.14 |
13.28 |
5 |
1.15 |
1.61 |
9.24 |
11.07 |
12.83 |
15.09 |
6 |
1.64 |
2.20 |
10.64 |
12.59 |
14.45 |
16.81 |
7 |
2.17 |
2.83 |
12.02 |
14.07 |
16.01 |
18.48 |
Table 17
(ii)
After analysing the results, the students stated that the inheritance of the seed colour and shape in their investigation was different from that in Mendel’s investigation.
Using Table 17, discuss whether the results of the investigation and the chi-squared test support the students’ statement.
[3]
(iii)
A ratio that is different from the expected 9:3:3:1, in a cross such as this, can be the result of epistasis.
Suggest and explain one reason, other than epistasis, why the phenotype ratio might not be 9:3:3:1.
Suggestion .......................................................
Explanation .....................................................
[3]