Classification & Evolution (OCR A Level Biology)

Exam Questions

3 hours38 questions
1a
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5 marks
(i)
Define the term ‘classification’.

 [2]

(ii)
Complete the list of taxonomic groups by filling in the gaps:

Domain

 

Phylum

 
 

Family

Genus

Species

[3]

1b
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2 marks

State two reasons why the classification of organisms is useful.

1c
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2 marks

The binomial system is a universal system used to name organisms. 

(i)
State which two taxonomic groups are included in the binomial of an organism. 

 [1]

(ii)
Explain why binomials are useful for scientists.
 [1]

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2a
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4 marks

Before the domain system was introduced in 1977, living organisms were originally classified into five kingdoms. 

(i)
Which kingdom were bacteria classified as?

[1] 

(ii)
State one similarity and two differences between the kingdoms plantae and animalia
[3]
2b
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5 marks

The domain system introduced the idea of classification by cell type. 

(i)
Describe the difference between prokaryotic and eukaryotic cells.

[2] 

(ii)

Prokaryotes have been further sub categorised into archaea and bacteria.

State the type of ribosomes that are found in archaea and bacteria. 

 [1]

(iii)
Describe one difference between archaea and bacteria.
[2]

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3a
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7 marks

Some organisms are better adapted to their environment than others. 

(i)
State what is meant by the term adaptation. 

 [1]

(ii)

Types of adaptation include anatomical, physiological and behavioural.

State what is meant by an organism’s physiological adaptations.

  [1]

(iii)

Some animals migrate from one area to another when food sources become depleted in the winter. 

Identify the type of adaptation that this is an example of.

  [1]

(iv)
Describe two anatomical adaptations.
[4]
3b
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2 marks

Describe what is meant by convergent evolution.

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4a
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4 marks
(i)
State what is meant by selection pressures. 

 [1]

(ii)
Give three examples of selection pressures that animals may experience. 
[3]
4b
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4 marks

Describe how natural selection occurs. 

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5a
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6 marks

Antibiotics are often prescribed to treat bacterial infections. Some bacteria have developed resistance to specific antibiotics. 

(i)
State what is meant by the term ‘resistance’ in this context. 

[1]

(ii)

The resistance of bacteria to antibiotics is an example of evolution by natural selection.

Describe how some bacteria becoming resistant to antibiotics can lead to the whole population of bacteria becoming antibiotic-resistant. 

   [3] 

(iii)
State two precautions that could be taken to reduce cases of antibiotic resistance. 

[2]

5b
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2 marks

Pesticides are chemicals often used in agriculture that kill pests including insects and fungi. Pesticide resistance in insects is a growing problem in farming.

Describe a consequence to humans of pesticide resistance in insects.

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1
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5 marks

Many algal species are unicellular organisms. Some occur in colonies of more than one cell.

Fig. 21.2 shows a typical algal cell.

q21b-paper-2-nov-2020-ocr-a-level-biology


Fig. 21.2

(i)
At various times, algae have been classified in different kingdoms.

Using the information given above, draw a conclusion about which kingdom is the most appropriate in which to classify algae.

In your answer explain why other kingdoms are not appropriate choices. 

[4]

(ii)
Suggest one piece of evidence not given above that could be used to provide strong support for the classification of algae in a particular kingdom.

[1]

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2a7 marks

The cheetah, Acinonyx jubatus, is a member of the cat family, Felidae.

Cheetahs display less intraspecific variation than other members of the family Felidae.

Fig. 20.1 shows the mean body length of a population of cheetahs from southern Africa.

The error bars on Fig. 20.1 show the standard deviation of mean body length.

q20-paper-2-june-2018-ocr-a-level-biology

Fig. 20.1

(i)
At between 2.5 and 4 years old, the mean length of female cheetahs is less than that of males.
Calculate how much shorter than males female cheetahs are.
Show your working. Express your answer as a percentage to two significant figures.
[2]
(ii)
Using only Fig. 20.1 and your answer to (i), what can be concluded about the significance of the difference between the length of male and female cheetahs aged between 2.5 and 4 years?
Explain your answer.
[2]
(iii)
A student looked at Fig. 20.1 and wrote:
The longest male cheetah that was measured was 1.52m long”.
Explain whether the information in Fig. 20.1 supports the student’s answer.
[1]
(iv)
State the likely causes of variation in body length in cheetahs.
[2]
2b5 marks

The population of cheetahs has been declining for the past 100 years and is estimated to be between 6000 and 7000.
Within the remaining cheetah population, intraspecific genetic diversity is very low.
One isolated population of cheetahs in Iran has fewer than 100 individuals.

(i)
State one way in which genetic diversity can be measured.
[1]
(ii)
It is thought that the modern cheetah population has low genetic diversity because the population, relatively recently, experienced a genetic bottleneck.

Explain why a genetic bottleneck can lead to low genetic diversity.
[2]
(iii)
Scientists are concerned about genetic drift in the remaining cheetah populations.

Explain why genetic drift is likely to be of particular concern in the population of 100 cheetahs in Iran.
[2]
2c8 marks

Madagascar is a large island off the coast of Africa that once formed part of the mainland.

The fossa, Cryptoprocta ferox is the top predator on Madagascar.

The fossa shares many physical similarities with cats but it is not a member of the family Felidae. It is related to the mongoose.

The mongoose is a much smaller mammal that lives on the African mainland.
Fig. 20.2 shows a fossa and a mongoose.

q20c-paper-2-june-2018-ocr-a-level-biology
Fig. 20.2
(i)
The mongoose is a smaller mammal and also has proportionally longer fur. State one other difference, visible in Fig. 20.2, between a fossa and a mongoose.
[1]
(ii)
When the island of Madagascar became separated from the African continent, there were no members of the cat family, Felidae, on the island.
Outline how a fossa could have evolved from a much smaller, mongoose-like ancestor.
[4]
(iii)
Islands, such as Madagascar, often have species that are different from those on the nearest land mass because they are reproductively isolated.

State three other conditions that must be present in order for speciation to occur.

1 ...............................................
2 ...............................................
3 ...............................................

[3]

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31 mark

Bacteria that are able to digest and metabolise the hydrocarbons in crude oil are more common in areas, such as around the coast of Alaska and the Gulf of Mexico, where oil spillages are common.

Suggest an explanation for this observation.

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4a
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3 marks

The effect of wave action on the height of the shells of the dog whelk (Nucella lapillus) was investigated by comparing an exposed shore and a sheltered shore.

q3-paper-3-specimen-ocr-a-level-biology

  • A random sampling technique was used to collect 50 shells from an exposed shore.
  • The shell height was measured from the base to the conical tip. The whelk was returned to its location.
  • The process was repeated for the sheltered shore.
  • All the results were recorded in Table 3.1.
Location Height of shell (mm) Range Mean SD
Sheltered
shore
26 28 27 26 28 23 28 23 26 28  
29 29 29 29 29 28 29 29 29 29
30 31 30 29 32 29 30 29 30 32
33 35 34 32 35 32 34 32 33 35
37 39 38 37 39 35 38 36 37 39 16 31.3 4.1
Exposed
shore
15 17 16 15 23 15 23 16 13 15  
17 24 18 17 17 14 17 18 16 17
19 19 20 24 18 20 19 20 18 20
23 14 24 14 21 20 23 17 21 23
25 25 28 26 25 27 25 28 25 27 15 20.0 4.2

Table 3.1

The t test can be used to determine the significance of the differences between shell height on the exposed shore and the sheltered shore.

(i)

Calculate the t value for the data using the formula:

t space equals space fraction numerator open vertical bar stack x subscript 1 with bar on top space minus space top enclose x subscript 2 end enclose close vertical bar over denominator square root of open parentheses fraction numerator s subscript 1 superscript 2 over denominator n subscript 1 end fraction plus space fraction numerator s subscript 2 superscript 2 over denominator n subscript 2 end fraction close parentheses end root end fraction

where,

open vertical bar stack x subscript 1 with bar on top space minus space top enclose x subscript 2 end enclose close vertical bar is the difference in mean values of sample 1 and sample 2

s subscript 1 superscript 2 and s subscript 2 superscript 2are the squares of the standard deviations of the samples

n1 and n2 are the sample sizes.

Give your answer to two decimal places.

 [2]

(ii)

The null hypothesis is that there is no difference between the means of the two shell populations.

The critical values at 98 degrees of freedom are shown in Table 3.2.

Degrees of freedom p = 0.10 p = 0.05 p = 0.01 p = 0.001
98 1.67 2.00 2.64 3.41

Table 3.2

Using the table of critical values, explain whether the student would be able to accept or reject the null hypothesis as a result of the t value you calculated in part (i).

[1]

4b
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4 marks

The students organised the data from Table 3.1 into classes.

The organised data is shown in Table 3.3.

Sheltered shore Exposed shore
Height (mm) Tally Total Height (mm) Tally Total
23–26 straight I up diagonal strike III 5 11–14 IIII 4
27–30 straight I up diagonal strike III space straight I up diagonal strike III space straight I up diagonal strike III space straight I up diagonal strike III space space II 22 15–18 straight I up diagonal strike III space II end strike 7
31–34 straight I up diagonal strike III space straight I up diagonal strike III space straight I 11 19–22 straight I up diagonal strike III space straight I up diagonal strike III space II 12
35–38 straight I up diagonal strike III space IIII 9 23–26 straight I up diagonal strike III space straight I up diagonal strike III space II 12
39–42 III 3 27–30 IIII 4

Plot the most suitable graph of the data given in Table 3.3.

q3b-paper-3-specimen-ocr-a-level-biology

4c
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3 marks

Use the data and graph to discuss any correlation between the height of the whelk shell and the type of shore.

Suggest explanations for your findings.

4d
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2 marks

Suggest a limitation of the procedure used to gather the data in this experiment and recommend how you could improve this.

4e
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1 mark

How could the students improve the accuracy of their data?

4f
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3 marks

Discuss the validity of the conclusions you have made during this experiment.

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5a
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2 marks

Termites are highly social insects. They are thought to have evolved from earlier forms of insect at least 150 million years ago, in the Jurassic geological period. They are related to cockroaches.

(i)
How might scientists a century ago have known that termites evolved in the Jurassic geological period?
[1]
(ii)
What new source of evidence might help today’s scientists to find out how closely related termites are to cockroaches?
[1]
5b
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6 marks

Fig. 5.1, shows a termite mound, the nest of approximately one million individuals.termite

Fig. 5.1

The photograph was taken in Queensland Australia, about 3000 kilometres south of the equator.

(i)
Fig. 5.1 shows that the interior of the termite mound is full of interconnecting chambers. At the top of the mound some of these chambers open to the air outside.

Worker termites spend all their time working in brood chambers low in the mound, where eggs and larvae develop.

Explain how carbon dioxide produced in the respiring body cells of worker termites is removed to the air outside the termite mound.
[4]
(ii)
In Africa, closer to the equator, the mounds built by some species of termite are blade-shaped, with the long axis pointing North–South. Fig. 5.2, shows an example of a termite mound in Africa.termite2
Fig. 5.2

Suggest why the African termites need to build mounds in this shape and orientation.
[2]
5c
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1 mark

Most termites eat only dead vegetable material, so their principle food source is cellulose.

Cellulose is a polymer.

State the name of the monomer in cellulose.

5d
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2 marks
Termites such as the species that built the mound in Fig. 5.1 can be classed as ‘keystone species’.



Use the information given to state one argument that supports this statement and one argument that does not.

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6a
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2 marks

Two species of chimpanzees, the chimpanzee and the bonobo, are the closest living relatives of humans.

Fig. 19.1 is a diagram representing the current classification of chimpanzees and humans within the Family Hominidae.

q19-paper-2-june-2017-ocr-a-level-biology

Fig. 19.1

Humans and chimpanzees are currently classified within the same family.

Chimpanzees were once classified separately from humans in the Family Pongidae along with gorillas and orang utans.

Fig. 19.2 shows a human hand and a chimpanzee hand.q19a-paper-2-june-2017-ocr-a-level-biology

Fig. 19.2

Describe two differences between the two images that could have been used to classify humans and chimpanzees in separate families.

6b
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11 marks

Differences between the nucleotide base sequences can be used to estimate the length of time since two species diverged from one another.

The greater the number of differences, the greater the length of time that has elapsed since the two organisms were part of the same species.

Fig. 19.3 shows the line of best fit for the differences in DNA between pairs of primate species plotted against the number of years since the two species diverged from a common ancestor.q19b-paper-2-june-2017-ocr-a-level-biology


Fig. 19.3

(i)
Calculate the rate of DNA change using the data in Fig. 19.3.

Give your answer to three significant figures.

Answer ............................% per million years [2]

(ii)
The mutation rate in mammals can vary by as much as 20% between species.

Use Fig. 19.3 to calculate the time since the phylogeny of humans diverged from chimpanzees, and the range over which this estimate may vary.

time since divergence = ...................................................
range = ...................................................................................
[2]

(iii)
Some scientists have suggested that humans and chimpanzees should be reclassified as belonging to the same genus.

Evaluate their suggestion using evidence from Figs. 19.1 to 19.3 and your own knowledge of the scientific basis for the classification of organisms.
 [6]
(iv)
One type of gene is known as a homeobox gene.

The base sequences of homeobox genes in humans and chimpanzees are almost identical.

What conclusions about the evolutionary relationship between humans and chimpanzees can be drawn from this piece of evidence?
 [1]

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7
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5 marks

Domesticated pigs are descended from Sus scrofa, sometimes called the ‘wild boar’.

(i)
In Table 17.1
  • number the levels in the correct sequence and
  • complete the name column.
Sequence of levels Level Name
......................... Order Artiodactyla
......................... Species .........................
......................... Family Suidae
1 Kingdom .........................
......................... Genus .........................
......................... Phylum Chordata
......................... Class Mammalia

Table 17.1

[4]

(ii)
We now have DNA evidence of how organisms are related to each other. This evidence has helped biologists to construct a second classification viewpoint: the Domain system.

Explain what such developments show about the nature of scientific knowledge.
[1]

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8a
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2 marks

The mean levels of human lactose intolerance vary in different parts of the world.

Table 18.1 shows the contrasting levels of lactose intolerance in two ethnic groups from different parts of the world.

Population Frequency of lactose intolerance phenotype
Europeans 0.05
Australian aborigines 0.97

Table. 18.1

The Hardy–Weinberg principle states that:

p + q = 1
p2 + 2pq + q2 = 1

Where p is the frequency of the dominant allele and q is the frequency of the recessive allele in the genotypes of a population.
  
The lactose intolerance allele is recessive to the mutant allele, which prevents lactose intolerance.
Calculate the frequency of the heterozygous genotype in the Australian aborigine population.

8b
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9 marks

Read the following five statements.

Mutations preventing lactose intolerance have occurred in humans at various times in the prehistoric past, and in all human races.

The domestication of large lactating mammals like goats and cattle arose in Europe and parts of Africa 5 000 to 10 000 years ago.

The lowest levels of lactose intolerance are found in areas that European populations colonised, like North America.

The ability of agricultural populations to digest the milk, as well as the meat, of animals, is advantageous. It adds to their general nutrition.

Until recent times the Australian aborigines had been isolated on their island continent for around 50 000 years.


Suggest how the lactose intolerance phenotype came to be present in only 5% of a population like the Europeans, but came to be present in 97% of the Australian aborigines. Use the information given above and knowledge of Darwin’s theory of evolution by natural selection.

8c
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1 mark

An Iron Age farm was excavated by archaeologists. Some DNA was recovered from the tooth of an animal thought to be a type of domesticated milk cow.

A farmer keeps rare breed cows similar to those farmed on the Iron Age farm. DNA from the cows was obtained.

What technique would you plan to use, to compare digested and amplified fragments from the two DNA samples?

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1a
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3 marks

The heights of limpets (Patella vulgta) on exposed and sheltered rocky shores were measured to determine the effect of wave action. Ten shells were randomly collected and their height measured in each location.

 The results are shown below:

Location Number of readings Mean height (mm) Standard deviation
Exposed rocky shore 10 12.2 1.55
Sheltered rocky shore 10 17.6  

(i)

State an appropriate null hypothesis for this investigation.
[1]
(ii)
The data used for the height of limpets on the sheltered rocky shore was:

18, 16, 17, 18, 16, 20, 19, 17, 18, 17

Calculate the standard deviation for this data.

[2]

1b
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5 marks
(i)
Using the Student’s t-test formula below, calculate the value of t for the data.

t equals fraction numerator top enclose straight X subscript 1 minus space top enclose straight X subscript 2 over denominator square root of open parentheses fraction numerator s subscript 1 superscript 2 over denominator n subscript 1 end fraction plus fraction numerator s subscript 2 superscript 2 over denominator n subscript 2 end fraction close parentheses end root end fraction

[3]

(ii)
The critical value for t at the significance level of 5% with 18 degrees of freedom is 1.734.

Use the value of t that you calculated in part (iii) to explain whether the null hypothesis should be accepted or rejected.

[2]

1c
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2 marks

Suggest a limitation of the procedure used to gather the data in this investigation and explain how this limitation could be improved.

1d
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2 marks

The investigation was repeated to improve the accuracy of the data.

Explain why this would not help.

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2a
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5 marks

A group of scientists investigated the relationship between the length and width of oak (Quercus robur) leaves.

Ten leaves were collected and their length and width measured with a ruler and recorded in the table below.

Leaf length (mm) Rank for leaf length Leaf width (mm) Rank for leaf width Difference in rank (d) d2
101 7 64      
92 1 58      
99 5 61      
103 9 67      
97 3 60      
100 6 65      
102 8 66      
96 2 59      
98 4 62      
104 10 63      
  ΣD2 =

(i)
Use the table above to calculate ΣD2 for this data.

[2]

(ii)
Use the formula below to calculate Spearman’s rank correlation coefficient for this data.
r subscript s space equals space 1 space minus space fraction numerator 6 straight capital sigma straight d squared over denominator straight n space open parentheses straight n squared minus 1 close parentheses end fraction
[3]



2b
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3 marks

The critical value of rs at the 5% level (n = 10) is 0.65. The scientists conclude that there is a genuine positive correlation between the length and width of oak leaves.

Evaluate this conclusion.

2c
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3 marks

In this investigation, the leaves were randomly selected from various oak trees.

Suggest three ways in which the validity of the sampling method could be improved.

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3a
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3 marks

The image below shows the leafy seadragon (Phycodurus eques), found along the southern and western coasts of Australia. The leafy seadragon has long leaf-like protrusions all over the body and small transparent fins which slowly undulate.

ocr-a-4-3h-sq-seadragon-image

(i)
With reference to the image and information above, suggest an adaptation of the leafy seadragon.

[1]

 

(ii)
The table shows some taxonomic descriptions for the leafy seadragon. They are not in the correct hierarchical sequence.

Complete the table to show the correct hierarchical sequence using the numbers 1 to 5.

Taxonomic description Hierarchical position
Class Actinopterygii  
Kingdom Animalia  
Order Syngnathiformes  
Phylum Chordata  
Family Syngnathidae  

[2]

3b
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4 marks

Heliconius are a genus of butterflies commonly known as longwings or heliconians. They are found in tropical and subtropical areas and feed upon poisonous plants, making them toxic to predators. 

Heliconius exhibits brightly coloured wing patterns as shown in the image below.

ocr-a-4-3h-sq-butterfly-image

The brightly coloured wing patterns signal the toxicity of the butterflies to predators and are controlled by one gene, named cortex, which was identified in 2016.

Over time, different species of Heliconius have evolved to have similar wing patterns. Explain how this is an example of natural selection.

3c
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2 marks

The brightly coloured wing patterns of Heliconius are thought to have developed through the process of Mullerian mimicry where organisms sharing common predators mimic each other's warning signals to their mutual benefit.

Explain why this is an example of convergent evolution.

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4a
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4 marks

Clostridium difficile (C. diff) is a bacterium which is resistant to multiple antibiotics including penicillins and tetracyclines.

Genes for antibiotic resistance are often found outside the main bacterial chromosomes.

(i)
Name the structures where these are found.

[1]

The genomes of some bacteria change through conjugation; the exchange of genetic information between bacterial cells when they are in close contact. The DNA repair process of this genetic information is less effective than in chromosomal DNA.

(ii)
Using the information above and your prior knowledge of bacteria, explain how features of bacteria may both increase and decrease genetic variation in populations.

[3]

4b
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5 marks

Explain why the number of antibiotic-resistant populations of bacteria such as Clostridium difficile are increasing.

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5a
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4 marks

The image below shows a phylogenetic tree showing the relationship between primate species. It is based on the DNA sequence of the gene that codes for cytochrome c.ocr-a-4-3h-sq-phylogenetic-tree

(i)
Use the phylogenetic tree to compare the relationships between the common chimp, gorilla and old world monkey.

[1]

(ii)
Explain how comparative biochemistry provides evidence of evolution.

[3]

5b
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3 marks

Cytochrome C has a tertiary structure and plays an important role as an electron carrier in respiration. There is found to be one difference in the cytochrome c sequence between humans and rhesus monkeys and ten differences in the cytochrome c sequence between humans and kangaroos.

Explain how Cytochrome C is able to perform the same function in these different species despite the differences in gene sequence.

5c
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2 marks

Cytochrome C is an integral protein to the oxidative phosphorylation stage of respiration.

Explain why this makes cytochrome C an important molecule used for DNA comparison between organisms.

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