Natural Selection: Hardy-Weinberg Principle (Cambridge (CIE) A Level Biology) : Revision Note
Natural selection: the Hardy-Weinberg principle
The Hardy-Weinberg principle can be used to predict allele frequencies in a population
The principle can only be applied accurately to populations under certain conditions, e.g. in populations where:
no natural selection is taking place
there is no migration into or out of the population
mating is random
the population is large
no mutations are occurring
Hardy-Weinberg equations
If the phenotype of a trait in a population is determined by a single gene with only two alleles (we will use B / b as examples throughout this section) then the population will consist of individuals with three possible genotypes:
Homozygous dominant (BB)
Heterozygous (Bb)
Homozygous recessive (bb)
When using the Hardy-Weinberg equation, frequencies are represented as proportions of the population; a proportion is a number out of 1
The frequency of alleles can be represented; this is the proportion of all of the alleles in a population that are of a particular form
The letter p represents the frequency of the dominant allele (B)
The letter q represents the frequency of the recessive allele (b)
As there are only two alleles at a single gene locus for a phenotypic trait in the population:
p + q = 1
E.g. in a population of 100 individuals there would be 200 alleles because every individual has two versions of each gene
If 120 of those alleles were the dominant allele then the frequency of the dominant allele would be 120/200
It could be said that p = 120 ÷ 200 = 0.6
If p = 0.6 then q = 1 - 0.6 = 0.4
The frequency of genotypes can also be represented; this is the proportion of all of the individuals with a particular genotype
The frequency of homozygous dominant individuals is represented by p2
The frequency of heterozygous individuals is represented by 2pq
The frequency of homozygous recessive individuals is represented by q2
As these are all the possible genotypes of individuals in the population the following equation can be constructed:
p2 + q2 + 2pq = 1
Worked Example
In a population of birds 10 % of the individuals exhibit the recessive phenotype of white feathers.
Calculate the frequencies of all genotypes. Use F / f to represent dominant and recessive alleles for feather colour.
Answer
Begin by working out:
the part of the Hardy-Weinberg equation that we have been given:
10 % recessive white phenotype ff
10 % = 0.1
q2 = 0.1
the part of the Hardy-Weinberg equation that we need to work out:
Frequency of the heterozygous genotype = 2pq
Frequency of the homozygous dominant genotype = p2
Step 1: find q
q2 = 0.1
q =
q = 0.32
Step 2: find p (the frequency of the dominant allele F).
If q = 0.32, and p + q = 1
p + q = 1
p = 1 - 0.32
p = 0.68
Step 3: Find p2 (the frequency of the homozygous dominant genotype)
0.682 = 0.46
p2 = 0.46
Step 4: Find 2pq (the frequency of the heterozygous genotype)
2 x (0.68) x (0.32) = 0.44
2pq = 0.44
Examiner Tips and Tricks
When you are using Hardy-Weinberg equations you must always start your calculations by determining which part of the equation you have been given, and which part you need to work out.
It is most common for questions to give the proportion of individuals that display the recessive phenotype; this is the only phenotype from which you can immediately work out its genotype as it will always be homozygous recessive.
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