Calculating Probabilities using Normal Distribution (AQA Level 3 Mathematical Studies (Core Maths))

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Naomi C

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Naomi C

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Maths

Calculating Probabilities using Normal Distribution

How do I find probabilities using a normal distribution?

  • The area under a normal curve between the points begin mathsize 16px style x equals a end style and begin mathsize 16px style x equals b end style is equal to the probability straight P left parenthesis a less than X less than b right parenthesis

    • Remember for a normal distribution so you do not need to worry about whether the inequality is strict (< or >) or weak (≤ or ≥)

  • The equation of a normal distribution curve is complicated so the area must be calculated numerically

  • When working with a normal distribution, you will be expected to find the probabilities by either using:

    • the distribution function on your calculator

    • or the statistical tables that are provided to you in the exam

How do I calculate, P(X = x) ,the probability of a single value for a normal distribution?

  • The probability of a single value is always zero for a normal distribution

    • You can picture this as the area of a single line is zero

    • straight P open parentheses X equals x close parentheses equals 0

  • Your calculator is likely to have a "Normal Probability Density" function

    • This is sometimes shortened to NPD, Normal PD or Normal Pdf

    • IGNORE THIS FUNCTION for this course!

    • This calculates the probability density function at a point NOT the probability

How do I calculate, P(a < X < b),  the probability of a range of values for a normal distribution?

  • You need a calculator that can calculate cumulative normal probabilities

  • You want to use the "Normal Cumulative Distribution" function

    • This is sometimes shortened to NCD, Normal CD or Normal Cdf

  • You will need to enter:

    • The 'lower bound' - this is the value a

    • The 'upper bound' - this is the value b

    • The 'µ' value - this is the mean

    • The '𝜎' value - this is the standard deviation

  • Check the order carefully as some calculators ask for standard deviation before mean

    • Remember it is asking for the standard deviation

    • If you have the variance make sure that you square root it

  • Always sketch a quick diagram to visualise which area you are looking for

Normal distribution curve with the area between two limits a and b shaded.

How do I calculate, P(X>a) or P(X<b) for a normal distribution?

  • You will still use the "Normal Cumulative Distribution" function on your calculator

  • straight P open parentheses X greater than a close parentheses can be estimated using an upper bound that is sufficiently bigger than the mean

    • Using a value that is more than 4 standard deviations bigger than the mean is quite accurate

    • Or an easier option is just to input lots of 9's for the upper bound (99999999.. or 1099)

Normal distribution curve with the area above a limit a shaded.
  • Similarly straight P open parentheses X less than b close parentheses can be estimated using a lower bound that is sufficiently smaller than the mean

    • Using a value that is more than 4 standard deviations smaller than the mean is quite accurate

    • Or an easier option is just to input lots of 9's for the lower bound with a negative sign (-99999999... or -1099)

Normal distribution curve with the area below a limit b shaded.
  • This works because the probability that X is more than 3 standard deviations bigger than the mean is less than 0.0015

    • This is the same for being 3 standard deviations less than the mean

    • This reduces to less than 0.000032 when using 4 standard deviations

Exam Tip

Make sure that when you're using your calculator to find probabilities, you enter the standard deviation and not the variance!

How can I use the statistical tables to calculate probabilities?

  • Sometimes you may be required to use statistical tables provided to you in the exam to calculate probabilities

    • Use Table 1: Normal distribution function

  • To calculate probabilities using this table you must first find the appropriate z-value using the formula z equals fraction numerator x minus mu over denominator sigma end fraction

  • To find straight P open parentheses X less than b close parentheses, trace along the relevant row and column to find the given probability

    • E.g. straight P open parentheses X less than 0.32 close parentheses equals 0.62552, find the value where the row 0.3 and the column 0.02 meet

Section of Table 1: Normal distribution function from the Data booklet. The probability for the z value 0.32 (0.62552) is highlighted.
Table 1: Normal distribution function
  • To find straight P open parentheses X greater than a close parentheses, use the identity straight P open parentheses X greater than a close parentheses equals 1 minus straight P open parentheses X less than a close parentheses

    • I.e. First find the probability that the random variable is less than the given value from the table, then subtract it from 1

  • To find straight P open parentheses a less than X less than b close parentheses, use the identity straight P open parentheses a less than X less than b close parentheses equals straight P open parentheses X less than b close parentheses minus straight P open parentheses X less than a close parentheses

    • I.e. Find the probabilities that the random variable is less than both given values, then subtract the lower one from the higher one

Worked Example

The mass of chickpeas, in grams, in a a group of tins is described by straight N open parentheses 250 comma space 14 squared close parentheses.

Work out the probability that a tin chosen at random will contain between 255 g and 265 g of chickpeas.

Using the Normal Cumulative Distribution function on your calculator, input the following values

a equals 255
b equals 265
mu equals 250
sigma equals 14

straight P open parentheses 255 less than X less than 265 close parentheses equals 0.21850...

21.9% (3 s.f.)

Worked Example

A group of school children are given a puzzle to complete. The time taken to complete the puzzle can be modelled by a normal distribution, with mean 15 minutes and standard deviation 2.4 minutes.

The statistical tables provided must be used to solve this problem.

Work out the probability that a child chosen at random takes less than 12 minutes to complete the puzzle.

Find the z-value for 12 minutes

z equals fraction numerator 12 minus 15 over denominator 2.4 end fraction equals negative 1.25

Sketch a diagram of the standard normal distribution
Remember that there are only positive z-values in the table so using the fact that the normal distribution is symmetrical about the mean

Diagram showing the standardised normal distribution for the time taken to complete a puzzle. The probabilities P(Z<-1.25) and P(Z>1.25) are shown to be equal.

straight P open parentheses Z less than negative 1.25 close parentheses equals straight P open parentheses Z greater than 1.25 close parentheses

So

straight capital phi open parentheses negative 1.25 close parentheses equals 1 minus straight capital phi open parentheses 1.25 close parentheses

On Table 1 from the statistical tables, find the row 1.2 and the column 0.05 and find the value that they both correspond to

z

...

0.04

0.05

0.06

...

...

...

...

...

...

...

1.1

...

0.87286

0.87493

0.87698

...

1.2

...

0.89251

0.89435

0.89617

...

1.3

...

0.90988

0.91149

0.91309

...

...

...

...

...

...

...

straight capital phi open parentheses 1.25 close parentheses equals 0.89435

Subtract from 1 to find straight capital phi open parentheses negative 1.25 close parentheses

1 minus 0.89435 equals 0.10565

straight P open parentheses X less than 12 close parentheses equals 0.10565

10.6% (3 s.f.)

Inverse Normal Distribution

Given the value of P(X < a) how do I find the value of a?

  • Your calculator will have a function called "Inverse Normal Distribution"

    • Some calculators call this InvN

  • Given that straight P open parentheses X less than a close parentheses equals p you will need to enter:

    • The 'area' - this is the value p

      • Some calculators might ask for the 'tail' - this is the left tail as you know the area to the left of a

    • The 'μ' value - this is the mean

    • The 'σ' value - this is the standard deviation

  • Always check your answer makes sense

    • If straight P open parentheses X less than a close parentheses is less than 0.5 then a should be smaller than the mean

    • If straight P open parentheses X less than a close parentheses is more than 0.5 then a should be bigger than the mean

    • A sketch will help you see this

  • If you are required to use the statistical tables to find a value of a for straight P open parentheses X less than a close parentheses equals p, use Table 2: Percentage points of the normal distribution

    • E.g. To find P open parentheses X less than a close parentheses equals 0.63, find the row 0.6 and the column 0.03, the value that corresponds to both is 0.3319

Section of Table 2: Percentage points of the normal distribution from the Data booklet. The percentage point for the probability of 0.63 (0.3319) is highlighted.
Table 2: Percentage points of the normal distribution
  • Remember that values found from the table are z-values from the standardised normal distribution

Given the value of P(X > a) how do I find the value of a  ?

  • Given straight P open parentheses X greater than a close parentheses equals p, use straight P open parentheses X less than a close parentheses equals 1 minus straight P open parentheses X greater than a close parentheses to rewrite this as straight P open parentheses X less than a close parentheses equals 1 minus p

  • Then use the method for straight P open parentheses X less than a close parentheses to find a

    • You can use your calculator or the statistical tables

  • If your calculator does have the tail option (left, right or centre) then you can use the "Inverse Normal Distribution" function straightaway by:

    • Selecting 'right' for the tail

    • Entering the area as 'p'

Worked Example

The mass of chickpeas, in grams, in a group of tins is described by straight N open parentheses 250 comma space 14 squared close parentheses.

27% of the tins contain less than mg.
Work out the value of m.

Using the Inverse Normal Distribution function on your calculator, input the following values

p equals 0.27
mu equals 250
sigma equals 14

For straight P open parentheses M less than m close parentheses equals 0.27, m equals 241.42061..

241 g (3 s.f.)

Worked Example

A group of school children are given a puzzle to complete. The time taken to complete the puzzle can be modelled by a normal distribution, with mean 15 minutes and standard deviation 2.4 minutes.

The statistical tables provided must be used to solve this problem.

83% of the children take less than x minutes to complete the puzzle.
Work out the value of x.

Using Table 2 from the statistical tables provided, use the row for 0.8 and the column for 0.03 to find the value associated with the probability 0.83

p

0.00

0.01

0.02

0.03

...

0.5

0.0000

0.0251

0.0502

0.0753

...

0.6

0.2533

0.2793

0.3055

0.3319

...

0.7

0.5244

0.5534

0.5828

0.6128

...

0.8

0.8416

0.8779

0.9154

0.9542

...

...

...

...

...

...

..

straight capital phi open parentheses z close parentheses equals 0.83, z equals 0.9542

Convert z-value back into time

table row cell 0.9542 end cell equals cell fraction numerator x minus 15 over denominator 2.4 end fraction end cell row cell 2.4 cross times 0.9542 end cell equals cell x minus 15 end cell row cell 2.4 cross times 0.9542 plus 15 end cell equals x row x equals cell 17.2900... end cell end table

17.3 minutes (3 s.f.)

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Naomi C

Author: Naomi C

Naomi graduated from Durham University in 2007 with a Masters degree in Civil Engineering. She has taught Mathematics in the UK, Malaysia and Switzerland covering GCSE, IGCSE, A-Level and IB. She particularly enjoys applying Mathematics to real life and endeavours to bring creativity to the content she creates.